(1/27)^(4-x)=9^(2x-1)

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Solution for (1/27)^(4-x)=9^(2x-1) equation: 



(1/27)^(4-x)=9^(2x-1)

We move all terms to the left:

(1/27)^(4-x)-(9^(2x-1))=0



Domain of the equation: 27)^(4-x)!=0

x∈R



We add all the numbers together, and all the variables

(+1/27)^(-1x+4)-(9^(2x-1))=0

We multiply all the terms by the denominator


(+1-((9^(2x-1)))*27)^(-1x+4)=0



We calculate terms in parentheses: +(+1-((9^(2x-1)))*27)^(-1x+4), so:

+1-((9^(2x-1)))*27)^(-1x+4

determiningTheFunctionDomain
-((9^(2x-1)))*27)^(-1x+1+4

We add all the numbers together, and all the variables

-1x-((9^(2x-1)))*27)^(+5

Back to the equation:

+(-1x-((9^(2x-1)))*27)^(+5)



We add all the numbers together, and all the variables

(-1x-((9^(2x-1)))*27)^5=0

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